Answer:
Proven below in the explanation
Step-by-step explanation:
Given that:
2x⁴-6x³+3x²+3x-2 ............. (1)
x²-3x+2 ................................ (2)
To proof that equation (1) is exactly divisible by equation (2), substitute an integer for 'x' in the two equations so as to form a whole number.
Assume x = 1
∴For equation (1)
= 2(1)⁴-6(1)³+3(1)²+3(1)-2
= 2 - 6 + 3 + 3 - 2
= 0
∴For equation (2)
= (1)²-3(1)+2
= 1 - 3 + 2
= 0
For x = 1, both equations are zero'0'
0/0 = 0
