[tex]\boxed { 5\left(2h+8\right)<60\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:h<2\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:2\right)\end{bmatrix} }[/tex]
Solution:
Given inequality is:
[tex]5(2h + 8) < 60[/tex]
We have to solve the inequality
From given,
[tex]5(2h + 8) < 60[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5\left(2h+8\right)}{5}<\frac{60}{5}\\\\\mathrm{Simplify}\\\\2h+8<12\\\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}\\\\2h+8-8<12-8\\[/tex]
[tex]\mathrm{Simplify}\\\\2h<4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{2h}{2}<\frac{4}{2}\\\\\mathrm{Simplify}\\\\h<2[/tex]
Thus the solution set is given as:
[tex]5\left(2h+8\right)<60\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:h<2\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:2\right)\end{bmatrix}[/tex]
