Respuesta :
The question is incomplete, here is the complete question:
The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)
Answer: The minimum volume of water that would be needed is 940.17 mL
Explanation:
We are given:
Solubility of substance X in water = 35.1 g/100 g
This means that 35.1 grams of substance X is dissolved in 100 grams of water
Applying unitary method:
If 35.1 grams of substance X is dissolved in 100 grams of water
So, 330.0 grams of substance X will be dissolved in = [tex]\frac{100}{35.1}\times 330=940.17g[/tex] of water
To calculate the volume of water, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of water = 1 g/mL
Mass of water = 940.17 g
Putting values in above equation, we get:
[tex]1g/mL=\frac{940.17g}{\text{Volume of water}}\\\\\text{Volume of water}=\frac{940.17g}{1g/mL}=940.17mL[/tex]
Hence, the minimum volume of water that would be needed is 940.17 mL
