A jet is coming in for a landing. It's currently 25,000 feet in
the air and the landing strip is 45,000 feet directly ahead. In
order to ensure a safe landing the plane needs to come in at no
more than a 30° angle of depression. Will this be a safe
landing?
Is this a safe landing?

A jet is coming in for a landing Its currently 25000 feet in the air and the landing strip is 45000 feet directly ahead In order to ensure a safe landing the pl class=

Respuesta :

The angle of depression is 29.0521°. So it is a safe landing.

Step-by-step explanation:

Step 1:

The plane is flying at a height of 25,000 feet and 45,000 feet away from the landing strip. Assume it lands with an angle of depression of x°.

So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 25,000 feet while the adjacent side measures 45,000 feet. The angle of the triangle is x°.

To determine the value of x, we calculate the tan of the given triangle.

[tex]tanx = \frac{opposite side}{adjacent side}.[/tex]

Step 2:

The length of the opposite side = 25,000 feet.

The length of the adjacent side = 45,000 feet.

[tex]tan x = \frac{25,000}{45,000} = 0.5555.[/tex]

So x = 29.0521°. Since x < 30°, it is a safe landing.