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A hydraulic lift is to be used to lift a 2500 kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed.

Respuesta :

Answer:here in Hydraulic system the pressure on both sides will remain the same

P_1 = P_2

\frac{F_1}{A_1} = \frac{F_2}{A_2}

\frac{mg}{\pi*\frac{10^2}{4}} = \frac{Mg}{\pi \frac{d^2}{4}}

\frac{25}{10^2} = \frac{1900}{d^2}

d = 87.2 cm

so its diameter is 87.2 cm

Explanation:

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