The answers are as follows,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr
Explanation:
All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.
It can be expressed as follows,
P1V1 = P2V2
Rearranging the above expression, we get,
[tex]$ V2 = \frac{P1V1}{V2}[/tex]
1) The first case can be solved as,
[tex]$V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}[/tex]
2) The second case can be solved as,
[tex]$V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L[/tex]
3) The third case can be solved as,
[tex]$P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}[/tex]
Thus the answers for all the three cases are found as,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr respectively
