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Raising 100 grams of water from 40 to 60 °C (the specific heat capacity of water is 1 sat) requires the addition of

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Answer:

2000 calories

Explanation:

Given the specific heat of water 1 cal/g  and mass as 100g:

[tex]Q=mc(\bigtriangleup T)\\=100g\times 1 cal/g\times (60-40)\\\\=2000c[/tex]

Hence an addition of 2000 calories is required.

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