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At an air show a jet flies directly toward the stands at a speed of 1190 km/h, emitting a frequency of 3580 Hz, on a day when the speed of sound is 342 m/s. What frequency (in Hz) is received by the observers?

Respuesta :

Answer:

The received frequency by the observers is 106.46 kHz.

Explanation:

Given that,

Speed = 1190 km/h = 330.5 m/s

Frequency = 3580 Hz

Speed of sound = 342 m/s

We need to calculate the received frequency by the observers

Using formula of frequency

[tex]f'=f(\dfrac{v+v_{o}}{v-v_{s}})[/tex]

Where, f = frequency

[tex]v_{o}[/tex] =velocity of observer

[tex]v_{s}[/tex] = velocity of source

Put the value into the formula

[tex]f'=\dfrac{342+0}{342-330.5}\times3580[/tex]

[tex]f'=106.46\ kHz[/tex]

Hence, The received frequency by the observers is 106.46 kHz.

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