The factor of the expression is [tex]7\left(9y^2+5y+4\right)[/tex]
Explanation:
The given expression is [tex]63y^2+35y+28[/tex]
We need to determine the factor of the expression.
The factor of the expression can be determined by simplifying the given expression.
Now, we shall rewrite each term as a multiple of 7.
Thus, rewriting, we have,
[tex]63=7\times9[/tex]
[tex]35=7\times5[/tex]
[tex]28=7\times4[/tex]
Hence, substituting these values in the expression, we get,
[tex](7\times9)y^2+(7\times5)y+(7\times4)[/tex]
Let us factor out the common term 7, we get,
[tex]7\left(9y^2+5y+4\right)[/tex]
Thus, the factor of the expression is [tex]7\left(9y^2+5y+4\right)[/tex]
The factor of the expression is determined by taking out the common term 7 from the expression.
