Respuesta :
Answer:
12.1, 12.3,12.4,12.5,12.3,12.1,12.2
[tex]\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271[/tex]
And for the standard deviation we can use the following formula:
[tex] s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And after replace we got:
[tex] s = 0.1496[/tex]
And as we can ee we got a small value for the deviation <1 on this case.
Step-by-step explanation:
For example if we have the following data:
12.1, 12.3,12.4,12.5,12.3,12.1,12.2
We see that the data are similar for all the observations so we would expect a small standard deviation
If we calculate the sample mean we can use the following formula:
[tex]\bar X=\frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex]\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271[/tex]
And for the standard deviation we can use the following formula:
[tex] s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And after replace we got:
[tex] s = 0.1496[/tex]
And as we can ee we got a small value for the deviation <1 on this case.
