Answer:
Molarity of [tex]HClO_{4}[/tex] solution is 0.311 M
Explanation:
Neutralization reaction: [tex]2HClO_{4}+Ba(OH)_{2}\rightarrow Ba(ClO_{4})_{2}+2H_{2}O[/tex]
According to balanced reaction, 1 mol of [tex]Ba(OH)_{2}[/tex] neutralizes 2 moles of [tex]HClO_{4}[/tex]
Number of moles of [tex]Ba(OH)_{2}[/tex] in 13.8 mL of 0.191 M [tex]Ba(OH)_{2}[/tex] solution = [tex]\frac{0.191}{1000}\times 13.8moles[/tex] = [tex]0.00264moles[/tex]
Let's assume molarity of [tex]HClO_{4}[/tex] solution is C (M) then-
Number of moles of [tex]HClO_{4}[/tex] in 17.0 mL of C (M) [tex]HClO_{4}[/tex] solution = [tex]\frac{C}{1000}\times 17.0moles[/tex] = [tex]0.017Cmoles[/tex]
Hence, [tex]0.017C=(2\times 0.00264)[/tex]
or, [tex]C=0.311[/tex]
So, molarity of [tex]HClO_{4}[/tex] solution is 0.311 M
