Answer:
9.4 m
Explanation:
This is a projectile motion. The maximum height above the level projection is given by
[tex]H = \dfrac{(v_0\sin\theta)^2}{2g}[/tex]
[tex]v_0[/tex] is the initial velocity, [tex]\theta[/tex] is the angle of projection above the horizontal and [tex]g[/tex] is the acceleration of gravity.
[tex]H = \dfrac{(20\sin40^\circ)^2}{2\times9.8} = \dfrac{165.27}{19.6} = 8.4\text{ m}[/tex]
The maximujm height above the ground is 1 m + 8.4 m = 9.4 m
