Answer:
A solid precipitate of [tex]SrCO_{3}[/tex] is formed when [tex]Na_{2}CO_{3}[/tex] and [tex]SrCl_{2}[/tex] are mixed.
Explanation:
A solid precipitate is formed only when an insoluble or sparingly soluble salt is formed through reaction between given reactants
According to solubility rule, all carbonates are insoluble except [tex]NH_{4}^{+}[/tex] and group IA compounds
So, a solid precipitate of [tex]SrCO_{3}[/tex] is formed when [tex]Na_{2}CO_{3}[/tex] and [tex]SrCl_{2}[/tex] are mixed together
Reactions: [tex]NaNO_{3}+KBr\rightarrow NaBr+KNO_{3}[/tex] (no precipitation)
[tex]Na_{2}CO_{3}+SrCl_{2}\rightarrow 2NaCl+SrCO_{3}[/tex] (precipitation)
[tex]2KOH+Na_{2}SO_{4}\rightarrow K_{2}SO_{4}+2NaOH[/tex] (no precipitation)
[tex]CuBr_{2}+2NaC_{2}H_{3}O_{2}\rightarrow Cu(C_{2}H_{3}O_{2})_{2}+2NaBr[/tex] (no precipitation)
