Answer:
[tex]sinA=\frac{12}{37} \\\\cosA=\frac{35}{37}\\\\ tanA=\frac{12}{35}[/tex]
Step-by-step explanation:
In the given triangle we have to find the ratios of [tex]sinA[/tex] ,[tex]cosA[/tex] and [tex]tan A[/tex]
Given:
[tex]Perpendicular= 12\\\\ Base= 35\\\\ Hypotenuse=37[/tex]
Ratio of [tex]sinA[/tex]
[tex]sinA= \frac{Perpendicular}{Hypotenuse} \\\\sinA= \frac{12}{37}\\[/tex]
Ratio of [tex]cosA[/tex]
[tex]cos A=\frac{Base}{Hypotenuse}\\\\ cosA=\frac{35}{37}[/tex]
Ratio of [tex]tan A[/tex]
[tex]tanA=\frac{Perpendicular}{Base} \\\\tanA=\frac{12}{35}[/tex]
