Answer:
x = 4 or x = -3
Step-by-step explanation:
[tex]\sqrt{x+12}=x[/tex]
Take square both the sides,
[tex](\sqrt{x+12})^{2}=x^{2}\\\\x+12=x^{2}[/tex]
x² - x - 12 = 0
x² - 4x + 3x - 3*4 =0
x*(x - 4) + 3*(x - 4)= 0
(x- 4 )(x+3) =0
x -4 =0 or x + 3 = 0
x = 4 or x = -3
