In the 18th century, the Chevalier de Mere asked Blaise Pascal to compare the probabilities of two events. Below, you will compute the probability of the two events that, prior to contrary gambling experience, were thought by de Mere to be equally likely. (Round your answers to four decimal places.) What is the probability of obtaining at least one 6 in four rolls of a fair die?

Respuesta :

Answer:

Step-by-step explanation:

The probability of getting a 6 in a throw of a fair die = [tex]\frac{1}{6}[/tex]

Therefore, the probaility of not getting a 6 in a throw of die is =[tex]1-\frac{1}{6}=\frac{5}{6}[/tex]

By compund probability theorem, the probability that in 4 throws a die no 5 is obtained = [tex][\frac{5}{6}]^4[/tex]

Hence the probability of obtaining 6 at least once in 4 throws of a die no 6 is obtained can be given as

=[tex]1-[\frac{5}{6}]^4=0.51775[/tex]