Answer:
Step-by-step explanation:
The probability of getting a 6 in a throw of a fair die = [tex]\frac{1}{6}[/tex]
Therefore, the probaility of not getting a 6 in a throw of die is =[tex]1-\frac{1}{6}=\frac{5}{6}[/tex]
By compund probability theorem, the probability that in 4 throws a die no 5 is obtained = [tex][\frac{5}{6}]^4[/tex]
Hence the probability of obtaining 6 at least once in 4 throws of a die no 6 is obtained can be given as
=[tex]1-[\frac{5}{6}]^4=0.51775[/tex]