Quadrilateral ABCD ​ is inscribed in this circle.



What is the measure of angle B?

Enter your answer in the box.

m∠B=
°

A quadrilateral inscribed in a circle. The vertices of the quadrilateral lie on the edge of the circle and are labeled as A, B, C, D. The interior angle B is labeled as left parenthesis 3 x minus 12 right parenthesis degrees. The angle D is labeled as x degrees.

Respuesta :

The measure of angle B is 132°

Explanation:

Given that the quadrilateral is inscribed in a circle.

The vertices A, B, C, D of a quadrilateral lie on the edge of the circle.

The angle B is given by [tex]\angle B=(3x-12)^{\circ}[/tex]

The angle D is given by [tex]\angle C=x^{\circ}[/tex]

We need to find the measure of angle B.

Since, the angles B and D are opposite angles.

Also, we know that the opposite angles of a quadrilateral are supplementary.

Thus, we have,

[tex]\angle B+\angle D=180^{\circ[/tex]

Substituting the values, we get,

[tex]3x-12+x=180[/tex]

      [tex]4x-12=180[/tex]

              [tex]4x=192[/tex]

                [tex]x=48[/tex]

Thus, the value of x is 48

Substituting the value of x in the angle B, we get,

[tex]\angle B=(3(48)-12)^{\circ}[/tex]

[tex]\angle B=(144-12)^{\circ}[/tex]

[tex]\angle B=132^{\circ}[/tex]

Thus, the measure of angle B is [tex]\angle B=132^{\circ}[/tex]

Answer: 132

Step-by-step explanation: Just confirming the answer :)