What are the magnitudes of (a) the angular velocity, (b) the radial acceleration, and (c) the tangential acceleration of a spaceship taking a circular turn of radius 3220 km at a speed of 29 000 km/h?

Respuesta :

Answer:

Part a)

Angular speed is given as

[tex]\omega = 2.50 \times 10^{-3} rad/s[/tex]

Part b)

Radial acceleration of the spaceship is given as

[tex]a_c = 20.15 m/s^2[/tex]

Part c)

Since we know that it is moving with constant speed

so tangential acceleration must be ZERO

Explanation:

As we know that tangential speed of the spaceship is given as

[tex]v = 29000 km/h[/tex]

[tex]v = 8055.55 m/s[/tex]

a)

Angular speed is given as

[tex]\omega = \frac{v}{R}[/tex]

[tex]\omega = \frac{8055.55}{3220\times 10^3}[/tex]

[tex]\omega = 2.50 \times 10^{-3} rad/s[/tex]

Part b)

Radial acceleration of the spaceship is given as

[tex]a_c = \omega^2 R[/tex]

[tex]a_c = (2.50 \times 10^{-3})^2(3220\times 10^3)[/tex]

[tex]a_c = 20.15 m/s^2[/tex]

Part c)

Since we know that it is moving with constant speed

so tangential acceleration must be ZERO