Answer:
m = 1.82E+23 kg
Explanation:
G = universal gravitational constant = 6.67E-11 N·m²/kg²
r = radius of orbit = 72,600 km = 7.26E+07 m
C = circumference of orbit = 2πr = 4.56E+08 m
P = period of orbit = 12.9 d = 1,114,560 s
v = orbital velocity of satellite Jim = C/P = 409 m/s
m = mass of Xandar = to be determined
v = √(Gm/r)
v² = [√(Gm/r)]²
v² = Gm/r
rv² = Gm
rv²/G = m
m = rv²/G
mG = universal gravitational constant = 6.67E-11 N·m²/kg²
r = radius of orbit = 72,600 km = 7.26E+07 m
C = circumference of orbit = 2πr = 4.56E+08 m
P = period of orbit = 12.9 d = 1,114,560 s
v = orbital velocity of satellite Jim = C/P = 409 m/s
m = mass of Xandar = to be determined
v = √(Gm/r)
v² = [√(Gm/r)]²
v² = Gm/r
rv² = Gm
rv²/G = m
m = rv²/G
m = 1.82E+23 kg