If the heat of combustion for a specific compound is − 1160.0 kJ / mol and its molar mass is 74.23 g / mol, how many grams of this compound must you burn to release 264.90 kJ of heat?

Respuesta :

Answer:

16.95 grams of this compound must be burn to release 264.90 kJ of heat.

Explanation:

The heat of combustion of a compound = [tex]\Delta H_{comb}=-1160.0 kJ/mol[/tex]

Suppose n moles of compound on combustion gives Q amount of energy

Q = -264.90 kJ

[tex]n\times \Delta H_{comb}=Q[/tex]

[tex]n=\frac{Q}{\Delta H_{comb}}=\frac{-264.90 kJ}{-1160.0 kJ/mol}=0.2284 mol[/tex]

Mass of 0.2284 moles of compound = m

Molar mass of compound = M = 74.23 g/mol

[tex]m=n\times M=0.2284 mol\times 74.23 g/mol=16.95 g[/tex]

16.95 grams of this compound must be burn to release 264.90 kJ of heat.