Answer:
The gravitational acceleration experienced was of 1.63m/s².
Explanation:
We know, from the kinematics equations of vertical motion that:
[tex]v^{2} =v_0^2-2gy[/tex]
Solving for g, we get:
[tex]g=-\frac{v^2-v_0^2}{2y}[/tex]
Since the final speed is zero, because Neil Armstrong came to a stop in his maximum height, we obtain:
[tex]g=\frac{v_0^2}{2y}[/tex]
Finally, we plug in the given values of the initial speed and the maximum height:
[tex]g=\frac{(1.51m/s)^2}{2(0.700m)}=1.63m/s^2[/tex]
This means that the gravitational acceleration experienced by Neil Armstrong in the moon, was of 1.63m/s².
