Answer: g decreases with the increase in height hence the ball hanging above 50 Km above the surface will show less wight.
Explanation: Acceleration due to gravity that we consider 9.8 [tex]m/s^{2}[/tex] (approx) varies with the height and depth.
As we go above the sea level the value of g decreases and follows the relation:
[tex]g_{h} = g_{0} \times (\frac{R}{R + h} )^{2}[/tex]
[tex]g_{h}[/tex] is the acceleration due to gravity at height h Km
[tex]g_{0}[/tex] is the acceleration due to gravity at sea level i.e 9.8 [tex]m/s^{2}[/tex]
R is the mean radius of earth i.e. 6378 km at the equator & 6357 km at pole.
h is he height where you wants to calculate the g.
Weight is defined as the pull force exerted on an object by earth's gravity.
Weight = mass [tex]\times[/tex] acceleration due to gravitational
W = mg
So, weight depends on the acceleration due to gravity. g decreases with the increase in height hence the ball hanging above 50 Km above the surface will show less wight.
