An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C . Calculate the specific heat of the unknown metal.

Respuesta :

Answer: The specific heat of the unknown metal is [tex]0.897J/g^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed=[tex]5040[/tex] Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = [tex]T_i[/tex]

Final temperature of the water = [tex]T_f[/tex]

Change in temperature ,[tex]\Delta T=T_f-T_i=(64.7)^0C[/tex]

Putting in the values, we get:

[tex]5040=86.8\times c\times 64.7^0C[/tex]

[tex]c=0.897J/g^0C[/tex]

The specific heat of the unknown metal is [tex]0.897J/g^0C[/tex]