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We are standing on the top of a 128 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h ( t ) = − 16 t 2 + 32 t + 128 . What is the highest point that the object reaches?

Respuesta :

Answer:

h(t) = -16[tex]t^{2}[/tex] + 32t + 128

h(t) = 128 feet

128 =  -16[tex]t^{2}[/tex]  + 32t + 128

-16[tex]t^{2}[/tex] + 32t + 128 - 128 = 0

-16[tex]t^{2}[/tex] + 32t  =

-16[tex]t^{2}[/tex]  = - 32t

divide through by 16t

  -16[tex]t^{2}[/tex]/ 16t      =    -32t/16t

   t =  2

t = 2 seconds

Step-by-step explanation:

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