Question not complete
Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the expected output will be 0 1 2 3 4 5
import java.util.Scanner;
public class CountToLimit {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
countLimit = scnr.nextInt();
printVal = 0;
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( /* Your solution goes here */ );
System.out.println("");
return;
}
}
Answer:
Replace while ( /* Your solution goes here */ );
With
while ( printVal <= countLimit );
This will check if the value of variable printVal is still within print range of variable countLimit.
The full program becomes
import java.util.Scanner;
public class CountToLimit {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
countLimit = scnr.nextInt();
printVal = 0;
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( printVal <= countLimit );
System.out.println("");
return;
}
}
Following are the Java program that uses the do-while loop:
import java.util.*;//import package
public class Main//defining the class
{
public static void main (String [] args)//defining the main method
{
int countLimit = 0, printVal = 0;//defining integer variable that initializes with value 0
Scanner obd= new Scanner(System.in);//creating the Scanner class object
countLimit = obd.nextInt();//input value into countLimit variable
do //defining do-while loop
{
System.out.print(printVal + " ");//printing the printVal value
printVal++;//incrementing the printVal value by 1
}
while (printVal<=countLimit);//using loop that check printVal value less than equal to countLimit value
}
}
Program Explanation:
Output:
Please find the attached file.
Note:
Find out more information about the do-while loop here:
brainly.com/question/25916519
