Answer:
The value of tension on the cable T = 1065.6 N
Explanation:
Mass = 888 kg
Initial velocity ( u )= 0.8 [tex]\frac{m}{sec}[/tex]
Final velocity ( V ) = 0
Distance traveled before come to rest = 0.2667 m
Now use third law of motion [tex]V^{2}[/tex] = [tex]u^{2}[/tex] - 2 a s
Put all the values in above formula we get,
⇒ 0 = [tex]0.8^{2}[/tex] - 2 × a ×0.2667
⇒ a = 1.2 [tex]\frac{m}{sec^{2} }[/tex]
This is the deceleration of the box.
Tension in the cable is given by T = F = m × a
Put all the values in above formula we get,
T = 888 × 1.2
T = 1065.6 N
This is the value of tension on the cable.
