Answer:
1st number is 50% larger than 2nd number.
The 2nd number is 33.33% smaller than 1st number.
Step-by-step explanation:
We have been given a pair of numbers (15 and 10). We are asked to find that by what percent of the first number is larger than the second number and by what percent of the second number is smaller than the first number smaller.
We will use percent change formula to solve our given problem as:
[tex]\text{Percent change}=\frac{\text{Final-Original}}{\text{Original}}\times 100\%[/tex]
[tex]\text{Percent change}=\frac{15-10}{10}\times 100\%[/tex]
[tex]\text{Percent change}=\frac{5}{10}\times 100\%[/tex]
[tex]\text{Percent change}=\frac{5}{1}\times 10\%[/tex]
[tex]\text{Percent change}=50\%[/tex]
Therefore, the 1st number is 50% larger than 2nd number.
[tex]\text{Percent change}=\frac{10-15}{15}\times 100\%[/tex]
[tex]\text{Percent change}=\frac{-5}{15}\times 100\%[/tex]
[tex]\text{Percent change}=-0.33333\times 100\%[/tex]
[tex]\text{Percent change}=-33.333\%[/tex]
Since the percent change is negative, this means that 2nd number is 33.33% smaller than 1st number.
The percent is negative because 15 decreased to 10.
