Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).
Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.
Mathematically it is given by the relation:
Impulse = Force [tex]\times[/tex] Time
According to the numerical values given in the question, I = 202 Ns and T = 0.244 s
So, Force F = [tex]\frac{Impulse}{Time}[/tex] = [tex]\frac{202}{0.244}[/tex] = 827.86 N
Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).
The magnitude of the average force exerted on the glove by the other boxer is 827.87 N.
Impulse is the product of force and time of a body. The S.I unit of impulse is N.s.
The formula of impulse is
I = Ft............... Equation 1
Where I = Impulse of a boxer, F = magnitude of the average force exerted on the glove, t = time.
make F the subject of the equation
F = I/t............... Equation 2
From the question,
Given: I = 202 N.s, t = 0.244 s
Substitute these values into equation 2
F = 202/(0.244)
F = 827.87 N
Hence, The magnitude of the average force exerted on the glove by the other boxer is 827.87
Learn more about Impulse here: https://brainly.com/question/11305319
