A sample of gas has a volume of 1.24 L under 2.35 atm pressure at 45°C. If the gas is then expanded to occupy a volume of 12.7 L at 0.515 atm, what is the temperature in degrees Celsius? Assume the number of moles of gas is held constant.

Respuesta :

Answer: The final temperature of the gas is 440°C

Explanation:

To calculate the temperature when volume and pressure has changed, we use the equation given by combined gas law.

The equation follows:

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1,V_1\text{ and }T_1[/tex] are the initial pressure, volume and temperature of the gas

[tex]P_2,V_2\text{ and }T_2[/tex] are the final pressure, volume and temperature of the gasW

We are given:

[tex]P_1=2.35atm\\V_1=1.24L\\T_1=45^oC=[45+273]K=318K\\P_2=0.515atm\\V_2=12.7L\\T_2=?[/tex]

Putting values in above equation, we get:

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

[tex]T(K)=T(^oC)+273[/tex]

[tex]713.75=T(^oC)+273\\\\T(^oC)=440^oC[/tex]

Hence, the final temperature of the gas is 440°C