Answer:
0.5 moles of LiOH will absorb 5.6 L of [tex]CO_2[/tex]
Explanation:
According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.
The balanced chemical equation is:
[tex]2LiOH+CO_2\rightarrow Li_2CO_3+H_2O[/tex]
2 moles of LiOH absorb 1 mole of [tex]CO_2[/tex] i.e. 22.4 Liters at STP
0.5 moles of LiOH absorb
=[tex]\frac{22.4}{2}\times {0.5}=5.6Liters[/tex]
0.5 moles of LiOH will absorb 5.6 L of [tex]CO_2[/tex]
