Answer:
The answer to the question is;
The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.
Explanation:
Based on NFPA guidelines we have for sales on street floor, the allowable occupant load factor per person is 30 ft²
That is where the floor area is 100,000 square feet we have the number of allowable occupant given by
(100,000 ft²)/(30 ft²/Person) = [tex]\frac{10000}{3} Persons[/tex] or 3,333 persons
That is the occupant load of the store if the floor area is 100,000 square feet = 3,333 persons
Based on m² we have 9,290 m² will require 2.8 m²/person
which gives;
(9,290 m²)/(2.8 m²/person) = [tex]\frac{9290}{2.8} Persons[/tex] = 23225/7 or 3,317.86 persons
Therefore applying safety, we go with the lesser number and we have
The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.
