Answer:
The vertical distance traveled is 3.18 m.
Explanation:
In order to find the vertical distance traveled by a body in free fall motion, starting from rest to a velocity of 7.9 m/s. For this purpose, we use Newton's third equation of motion,
2as = Vf² - Vi²
where,
a = g = 9.8 m/s²
s = vertical distance = Δy = ?
Vf = final velocity = 7.9 m/s
Vi = initial velocity = 0 m/s
Therefore,
2(9.8 m/s²)Δy = (7.9 m/s)² - (0 m/s)²
Δy = (7.9 m/s)²/(2)(9.8 m/s²)
Δy = 3.18 m