Answer:
Explanation:
Reaction force of inclined surface
R = mgcos30
=60 x 9.8 x .866
= 509 N
Force of kinetic friction
= .12 x 509
= 61.08 N
b )
net force downwards = mgsinθ - μmgcosθ
acceleration = g sinθ - μgcosθ
9.8 sin30 - .12 x 9.8 x cos30
= 4.9 - 1.018
a= 3.88 m /s²
c )
v² = 2as
= 2 x 3.88 x 20
v = 12.46 m /s
(a) The force is "61.08 N".
(b) The acceleration is "3.88 m/s²".
(c) The speed is "12.46 m/s".
Given:
Mass,
Angle,
Coefficient of Kinetic friction,
According to the question,
Reaction force of inclined surface will be :
→ [tex]R = mg Cos \Theta[/tex]
[tex]= 60\times 9.8\times 0.866[/tex]
[tex]= 509 \ N[/tex]
(a)
The force of Kinetic friction will be:
= [tex]0.12\times 509[/tex]
= [tex]61.08 \ N[/tex]
(b)
The acceleration will be:
= [tex]g Sin\Theta - \mu g Cos\Theta[/tex]
= [tex]9.8 Sin 30^{\circ}-0.12\times 9.8\times Cos 30^{\circ}[/tex]
= [tex]4.9-1.018[/tex]
= [tex]3.88 \ m/s^2[/tex]
(c)
The speed will be:
→ [tex]v^2 = 2as[/tex]
[tex]= 2\times 3.88\times 20[/tex]
[tex]= 155.2[/tex]
[tex]v = \sqrt{155.2}[/tex]
[tex]v = 12.46 \ m/s[/tex]
Thus the above answers are appropriate.
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