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Two capacitors with capacitances of 1.5 mF and 0.25 mF, respectively, are connected in parallel. The system is connected to a 50-V battery. What electrical potential energy is stored in the 1.5-mF capacitor?

Respuesta :

akande212

Answer:

Energy U = 1.875J

Explanation:

The voltage applied across the capacitors is the same and equal to 50V. The energy stored in a capacitor is given by

U = 1/2×CV²

So on substituting the required quantities into the equation we get U.

See attachment below.

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asuwafohjames

The energy stored in the 1.5-mF capacitor is 1.875 J.

To calculate the electric potential energy stored in the capcitor, we use the formula below.

Formula:

  • E = CV²/2............ Equation 1

Where:

  • E = electric potential energy
  • C = The 1.5 mF capacitor
  • V = Voltage.

From the question,

Given:

  • C = 1.5 mF = 1.5×10⁻³ F
  • V = 50 V

Substitute these values into equation 1

  • E = (1.5×10⁻³)(50²)/2
  • E = 1.875 J.

Hence, The energy stored in the 1.5-mF capacitor is 1.875 J.

Learn  more about electric energy here: https://brainly.com/question/1592046

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