A compound of molar mass 161 g/mol contains only carbon, hydrogen, bromine, and oxygen. Analysis reveals that the compound contains 12 times as much carbon as hydrogen by mass.Find the molecular formula.Express your answer as a chemical formula.

Respuesta :

Explanation:

It is known that,

       Molar mass of Br = 80 g/mol

       Molar mass of O = 16 g/mol

       Molar mass of H = 1.09 g/mol

      Molar mass of C = 12 g/mol

Now, total mass of the compound is calculated as follows.

         [tex]x + 12x + m \times 16 + 80[/tex] = 161

             13x + 16 m + 80 = 161

We assume that m = 1. Hence, the value of x will be as follows.

            x = [tex]\frac{81 - 16}{13}[/tex]

               = 5

As per the formula 12x = 12y

or,        x = y = 5

Therefore, molecular formula of the given compound is [tex]C_{5}H_{5}BrO[/tex].