Answer:
The volume for the reaction is 49.2 mL
Explanation:
We define the reaction where 1 mol of solid Zn reacts with 2 moles of hydrochloric to produce zinc chloride and hydrogen
The equation is:
Zn (s) + 2 HCl (aq) ⟶ ZnCl₂ (aq) + H₂(g)
First of all, we convert the mass of Zn to moles → 8.05 g / 65.41 g/mol = 0.123 moles
Ratio is 1:2. Then 0.123 moles will need the double of moles of HCl to react. (0.123 . 2 ) = 0.246 moles
We do not know the volume, but we have the molarity of the acid.
Molarity = moles of solute / volume (L) of solution
Therefore, volume (L) of solution = moles of solute / Molarity
Volume (L) of solution = 0.246 moles / 5 mol/L = 0.0492 L
0.0492L = 49.2 mL
