Answer:
[tex]-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C[/tex]
Step-by-step explanation:
-The questions asks us to integrate and find the integrals of the given function.
-We are given no limits and therefore we will find a generalized integral with a constant.
-Given the function [tex]\int{-\frac{2}{7}x^3-4x^4-2x} \, dx[/tex].
We can integrate the function as:
[tex]\int{-\frac{2}{7}x^3-4x^4-2x} \, dx\\\\=-\frac{2}{7\times4}x^4-\frac{4}{5}x^5-\frac{2}{2}x^2+C\\\\=-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C[/tex]
Hence the integral of the function is [tex]-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C[/tex]
