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A certain lightbulb has a tungsten filament with a resistance of 21.7 Ω when at 20.0°C and 146 Ω when hot. Assume the resistivity of tungsten varies linearly with temperature even over the large temperature range involved here. Find the temperature of the hot filament.

Respuesta :

Answer:

1321.57 °C

Explanation:

Using,

R = R'[1+α(T-T')]....................... Equation 1

Where R = final resistance of the tungsten filament, R' = Initial resistance of the tungsten filament, T = Final Temperature, T' = Initial temperature, α = Temperature coefficient of tungsten filament.

Make T the subject of the equation,

T = [(R-R')/R'α]+T'.................... Equation 2

Given: R = 146 Ω, T' = 21.7 Ω, T = 20 °C,

Constant: α =  0.004403/°C

Substitute into equation 2

T = [(146-21.7)/(21.7×0.004403)]+20

T = (124.3/0.0955)+20

T = 1321.57 °C

The temperature of the hot tungsten filament is;

T = 1292.91 °C

The formula for resistance at a temperature T of the hot filament is;

R(T) = R_o(1 + α(T - T_o))

Where;

R(T) = resistance at temperature T

R_o = resistance at temperature To

T_o = Temperature when cold

T is temperature when hot

α is temperature coefficient of resistance

We are given;

R_o = 21.7 Ω

T_o = 20°C

R(T) = 146 Ω

α for tungsten filament online is 0.0045 /°C

Thus;

146 = 21.7(1 + 0.0045(T - 20))

146/21.7 = (1 + 0.0045(T - 20))

6.72811 - 1 = 0.0045T - 0.09

0.0045T = 5.72811 + 0.09

0.0045T = 5.81811

T = 5.81811/0.0045

T = 1292.91 °C

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