The credit scores of 35-year-olds applying for a mortgage at Ulysses Mortgage Associates are normally distributed with a mean of 600 and a standard deviation of 100. (a) Find the credit score that defines the upper 5 percent. (Use Excel or Appendix C to calculate the z-value. Round your final answer to 2 decimal places.) Credit score 764.50 (b) Seventy-five percent of the customers will have a credit score higher than what value

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Answer:

a) The credit score that defines the upper 5% is 764.50.

b) Seventy-five percent of the customers will have a credit score higher than 532.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 600, \sigma = 100[/tex]

(a) Find the credit score that defines the upper 5 percent.

Value of X when Z has a pvalue of 1-0.05 = 0.95. So X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 600}{100}[/tex]

[tex]X - 600 = 1.645*100[/tex]

[tex]X = 764.5[/tex]

The credit score that defines the upper 5% is 764.50.

(b) Seventy-five percent of the customers will have a credit score higher than what value

100 - 75 = 25

This the 25th percentile, which is the value of X when Z has a pvalue of 0.25. So it ix X when Z = -0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.675= \frac{X - 600}{100}[/tex]

[tex]X - 600 = -0.675*100[/tex]

[tex]X = 532.5[/tex]

Seventy-five percent of the customers will have a credit score higher than 532.5.