Answer:
(a) 2.42 N
(b) 2.8 N
Explanation:
Parameters given:
Current, I = 4A
Length of wire, L = 2.8m
Magnetic field strength, B = 0.25 T
Magnetic force is given as:
F = I*L*B*sinθ
(a) When θ = 60°:
F = 4 * 2.8 * 0.25 * sin60
F = 2.42N
(b) When θ = 90°:
F = 4 * 2.8 * 0.25 * sin90
F = 2.8N
Answer:
(a) 2.425 N
(b) 2.8 N
Explanation:
(a)
The force on wire carrying current in a magnetic field is given as,
F = BILsinФ....................... Equation 1
Where F = magnetic force on the wire, B = Magnetic Field, I = Current, L = Length, Ф = angle between the magnetic Field and the current.
Given: B = 0.25 T, L = 2.8 m, I = 4 A, Ф = 60°
Substitute into equation 1
F = 0.25(4)(2.8)sin60°
F = 2.8×0.866
F = 2.425 N.
(b)
Similarly,
F = BILsinФ
Given: B = 0.25 T, L = 2.8 m, I = 4 A, Ф = 90°.
Substitute into the equation above
F = 0.25(2.8)(4)sin90°
F = 2.8(1)
F = 2.8 N
