Answer:
Explanation:
1)
As we know by the formula of speed of sound we have
[tex]v = 332 + 0.6 t[/tex]
[tex]t = 20 deg C[/tex]
[tex]v = 332 + (0.6 \times 20)[/tex]
[tex]v = 332 + 12 = 344 m/s[/tex]
So approx speed of the sound is nearly 340 m/s
so its TRUE
2)
Wave speed is given as
[tex]v = \frac{\lambda}{T}[/tex]
so it is given as
[tex]v = f \lambda[/tex]
TRUE
3)
[tex]f = \frac{1}{T}[/tex]
so from above equation we have
[tex]v = f \times \lambda[/tex]
[tex]v = \frac{\lambda}{T}[/tex]
4)
Wavelength is given as
[tex]\lambda = \frac{v}{f}[/tex]
[tex]\lambda = \frac{340}{440}[/tex]
[tex]\lambda = 0.773 m[/tex]
5)
As we know that
[tex]f = 50 Hz[/tex]
[tex]\lambda = 2.0 m[/tex]
so we will have
[tex]v = \lambda f[/tex]
[tex]v = 50 \times 2[/tex]
[tex]v = 100 m/s[/tex]