Respuesta :
Answer:
The answer to your question is C₂H₆O
Explanation:
Data
Compound CxHyOz
mass of the sample = 0.9827
mass of CO₂ = 1.90 g
mass of H₂O = 1.070 g
Process
1.- Find the moles and grams of Carbon
44g of CO₂ ------------------ 12 g of C
1.9 g of CO₂ --------------- x
x = (1.9 x 12) / 44
x = 0.52 g
12 g of C --------------------- 1 mol
0.52 g -------------------- x
x = (0.52 x 1) / 12
x = 0.043 moles
2.- Find the moles and grams of Hydrogen
18 g of H₂O ----------------- 2 g of H
1.07 g of H₂O -------------- x
x = (1.07 x 2)/18
x = 0.12 g of H
1 g of H -------------------- 1 mol of H
0.12 g --------------------- x
x = (0.12 x 1)/1
x = 0.12 moles of H
3.- Calculate the moles and grams of Oxygen
Mass of Oxygen = 0.9827 - 0.12 - 0.52
= 0.3427 g
16 g of O ----------------- 1 mol
0.3427 g ---------------- x
x = (0.3427 x 1) / 16
x = 0.021 moles
4.- Divide by the lowest number of moles
Carbon 0.043 / 0.021 = 2
Hydrogen 0.12 / 0.021 = 5.7 ≈ 6
Oxygen 0.021 / 0.021 = 1
5.- Write the empirical formula
C₂H₆O
Answer:
The empirical formula of the compound is C4H11O2
Explanation:
Step 1: Data given
Mass of the sample = 0.9827 grams
Mass of CO2 produced = 1.900 grams
Mass of H2O produced = 1.070 grams
Molar mass of CO2 = 44.01 g/mol
Molar mass of H2O = 18.02 g/mol
Molar mass of O2 = 32.0 g/mol
Step 2: Calculate moles CO2
Moles CO2 = mass CO2 / molar mass CO2
Moles CO2 = 1.900 grams / 44.01 g/mol
Moles CO2 = 0.04317 moles
Step 3: Calculate moles C
In 1 mol CO2 we have 1 mol C
For 0.04317 moles CO2 we have 0.04317 moles C
Step 4: Calculate mass C
Mass C = 0.04317 moles * 12.01 g/mol
Mass C = 0.5185 mass
Step 5: Calculate moles H2O
Moles H2O = 1.070 grams / 18.02 g/mol
Moles H2O = 0.05938 moles
Step 6: Calculate moles H
In 1 mol H2O we have 2 moles H
In 0.05938 moles H2O we have 2*0.05938 = 0.11876 moles H
Step 7: Calculate mass H
Mass H = 0.11876 * 1.01 g/mol
Mass H = 0.1199 grams
Step 8: Calculate mass O
Mass O = 0.9827 grams - 0.5185 grams - 0.1199 grams
Mass O = 0.3443 grams
Step 9: Calculate moles O
Moles O = 0.3443 grams / 16.0 g/mol
Moles O = 0.02152 moles
Step 10: Calculate mol ratio
We divide by the smallest amount of moles
C: 0.04317 moles / 0.02152 moles = 2
H: 0.11876 moles / 0.02152 moles = 5.5
O: 0.02152 moles / 0.02152 moles = 1
For each 2 C atoms we have 5.5 H atoms and 1 O atom
This means for each 4 C atoms we have 11 H atoms and 2 O atoms
The empirical formula of the compound is C4H11O2
