Answer:
x=2
Step-by-step explanation:
let x be the edge length of the square removed at each corner;
Hence the area of the base is:
[tex]A_b(80-2x)(40-2x)=2736\\\\3200-160x-80x+4x^2=2736\\\\\\4x^2-240x+3200=2736\\\\4x^2-240x+464=0\\\\x^2-60x+116=0[/tex]
Using the quadratic equation formula, or completing the square, x, or length of a side of one of the squares is x=2 or x=58
#Given that x=58 is larger than 40cm, the side length is x=2