Answer:
The mass of air that has entered the tank is 8.86Kg
Explanation:
We are given:
[tex] Size of tank= 2.15m^3
density = 1.18kg/m^3
new density = 5.30kg/m^3 [/tex]
We first calculate the intial and final masses,
Therefore:
[tex] M_initial = p_initial * V [/tex]
= 1.18 * 2.15 = 2.54
[tex] M_final = p_final * V [/tex]
= 5.30 * 2.15 = 11.4
Therefore to find the mass of air inside the tank, we use:
[tex] ΔM = M_final - M_initial [/tex]
= 11.4 - 2.54 = 8.86Kg
Therefore the mass of air inside the tank is 8.86Kg
Answer: The mass of the air that has entered the tank is 8.858kg
Explanation:
Before we can solve to obtain the mass of air that recently gained access into the tank, we must calculate the density of the air that just entered the tank. It is obtained by subtracting the previous density in the tank from the new density in the tank:
= 5.30kg/m^3 - 1.18kg/m^3
= 4.12kg/m^3
So, the density of the air that entered the tank recently is
4.12kg/m^3.
To find the mass of the air, we apply the formula for calculating density and make mass (m), the subject of the formula:
Density = mass/volume
Therefore, mass = Density × volume
The density of the air is 4.12kg/m^3.
The volume of the tank occupied by the air = 2.15m^3
Then, the mass of the air that just entered the tank is:
= 4.12 × 2.15
= 8.858kg
