Answer:
0.717 L
Explanation:
First, we will calculate the moles corresponding to 1.30 g of carbon dioxide (MW 44.01).
1.30 g × (1 mol/44.01 g) = 0.0295 mol
The pressure, in atm, is:
740 torr × (1 atm/760 torr) = 0.974 atm
The temperature, in Kelvin, is:
15.0°C + 273.15 = 288.2 K
We can find the volume of the gas using the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.0295 mol × 0.0821 atm.L/mol.K × 288.2 K / 0.974 atm
V = 0.717 L