Respuesta :

Padoru

The equation for a circle with a center at [tex](h,k)[/tex] and radius [tex]r[/tex] is the following:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

We are given a center of [tex](-4,0)[/tex] and we are also given that the radius is 8. Plus these values into the standard equation for a circle:

[tex](x-(-4))^2+(y+0)^2=8^2[/tex]

After simplifying, the equation turns into:

[tex](x+4)^2+y^2=64[/tex]

This should be your answer. Let me know if you need any clarifications, thanks!

~ Padoru