Respuesta :

Answer:

[tex]8\frac{11}{12}[/tex]

Step-by-step explanation:

In order to answer this question you will have to subtract 3 1/3 from 12 1/4 by turning the mixed fractions into improper fractions, finding the common denominator, (CD) then subtracting the numerators.

[tex]12 \frac{1}{4} - 3\frac{1}{3}[/tex]

Turn the mixed fractions into improper fractions:

[tex]12\frac{1}{4} = \frac{49}{4}[/tex]

[tex]3\frac{1}{3} = \frac{10}{3}[/tex]

[tex]\frac{49}{4} -\frac{10}{3}[/tex]

Find the common denominator:

[tex]4\times3=12[/tex]

[tex]3\times4=12[/tex]

[tex]CD=12[/tex]

[tex]49 \times 3 =147[/tex]

[tex]=\frac{147}{12}[/tex]

[tex]10\times4=40[/tex]

[tex]=\frac{40}{4}[/tex]

Now subtract the numerators:

[tex]147-40=107[/tex]

[tex]=\frac{107}{12}[/tex]

Turn the improper fraction into a mixed fraction:

[tex]\frac{107}{12} =8\frac{11}{12}[/tex]

[tex]=8\frac{11}{12}[/tex]

Hope this helps.

Answer:

Step-by-step explanation:

See,

3   1             12   1

    3                  4

you would have to multiply both bottoms to 12, then you would get 12 1/12 and 3 1/12 so when subtracting the top would go to zero which would make everything 0 so then it would just be a whole number subtraction problem and 12-3=9