Respuesta :
Answer:
[tex]8\frac{11}{12}[/tex]
Step-by-step explanation:
In order to answer this question you will have to subtract 3 1/3 from 12 1/4 by turning the mixed fractions into improper fractions, finding the common denominator, (CD) then subtracting the numerators.
[tex]12 \frac{1}{4} - 3\frac{1}{3}[/tex]
Turn the mixed fractions into improper fractions:
[tex]12\frac{1}{4} = \frac{49}{4}[/tex]
[tex]3\frac{1}{3} = \frac{10}{3}[/tex]
[tex]\frac{49}{4} -\frac{10}{3}[/tex]
Find the common denominator:
[tex]4\times3=12[/tex]
[tex]3\times4=12[/tex]
[tex]CD=12[/tex]
[tex]49 \times 3 =147[/tex]
[tex]=\frac{147}{12}[/tex]
[tex]10\times4=40[/tex]
[tex]=\frac{40}{4}[/tex]
Now subtract the numerators:
[tex]147-40=107[/tex]
[tex]=\frac{107}{12}[/tex]
Turn the improper fraction into a mixed fraction:
[tex]\frac{107}{12} =8\frac{11}{12}[/tex]
[tex]=8\frac{11}{12}[/tex]
Hope this helps.
Answer:
Step-by-step explanation:
See,
3 1 12 1
3 4
you would have to multiply both bottoms to 12, then you would get 12 1/12 and 3 1/12 so when subtracting the top would go to zero which would make everything 0 so then it would just be a whole number subtraction problem and 12-3=9