Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
How many combination of random samples of 4 students can be selected?
4 from a set of 12. So
[tex]C_{n,x} = \frac{12!}{4!(8)!} = 495[/tex]
495 combinations of 4 students can be selected.
