Answer:
(a) -4 m/s^2
(b) 20 m
Explanation:
Given:
u = 30 m/s
v = 10 m/s
t = 5 s
(a)
v = u + at (1st equation of motion)
On rearranging the terms we get,
a = v - u/t = 10 - 30/5 = -4 m/s^2
(b)
s = ut + (1/2)at^2 (2nd equation of motion)
s = 30(t) + (1/2)(-4)t^2
Distance it moves during the third second = Distance it moves in 3 seconds - Distance it moves in 2 seconds
S3 = s3 - s2
S3 = 30(3) + (1/2)(-4)(3)^2 - (30(2) + (1/2)(-4)(2)^2)
On solving we get,
S3 = 20 m
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