Answer:
The probability is approximately one in a million (0.001% ).
It's a very little probability, so the manager would be really surprised.
Step-by-step explanation:
We have for this question to calculate with a binomial random variable, with n=6 and p=1/1200=0.00083 .
We have to calculate the probability of getting 2 hits in the sample of size 6.
[tex]P(x=2)=\binom{6}{2}p^2(1-p)^4=15*(1/1200)^2*(1199/1200)^4\\\\P(x=2)=15* 0.000000694*0.996670831= 0.00001038[/tex]
The probability is approximately one in a million (0.001% ).
It's a very little probability, so the manager would be really surprised.
